  {"id":5347,"date":"2025-12-16T09:13:17","date_gmt":"2025-12-16T15:13:17","guid":{"rendered":"https:\/\/www.eastcentral.edu\/learning-center\/?page_id=5347"},"modified":"2025-12-16T09:19:38","modified_gmt":"2025-12-16T15:19:38","slug":"trigonometry-cheat-sheet","status":"publish","type":"page","link":"https:\/\/www.eastcentral.edu\/learning-center\/math-resources\/trigonometry-cheat-sheet\/","title":{"rendered":"Trigonometry Cheat Sheet"},"content":{"rendered":"\n<h2 class=\"wp-block-heading has-text-align-center has-medium-font-size\">Definition of the Trig Functions<\/h2>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Right triangle definition<\/strong><br>For this definition we assume that<\/p>\n\n\n\n$$\n0 < \\theta < \\frac{\\pi}{2} \\quad \\text{or} \\quad 0^\\circ < \\theta < 90^\\circ\n$$\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"408\" height=\"226\" src=\"https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-1.png\" alt=\"Right triangle with angle \u03b8 at the lower right; the bottom side is labeled adjacent, the vertical left side is labeled opposite, and the slanted side is labeled hypotenuse, with a right angle at the lower left corner.\" class=\"wp-image-5353\" style=\"width:394px;height:auto\" srcset=\"https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-1.png 408w, https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-1-300x166.png 300w\" sizes=\"auto, (max-width: 408px) 100vw, 408px\" \/><\/figure>\n<\/div>\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n$$\n\\sin \\theta = \\frac{\\text{opposite}}{\\text{hypotenuse}}\n\\qquad\n$$\n$$\n\\cos \\theta = \\frac{\\text{adjacent}}{\\text{hypotenuse}}\n\\qquad\n$$\n$$\n\\tan \\theta = \\frac{\\text{opposite}}{\\text{adjacent}}\n\\qquad\n$$\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n$$\n\\csc \\theta = \\frac{\\text{hypotenuse}}{\\text{opposite}}\n$$\n\n$$\n\\sec \\theta = \\frac{\\text{hypotenuse}}{\\text{adjacent}}\n$$\n\n$$\n\\cot \\theta = \\frac{\\text{adjacent}}{\\text{opposite}}\n$$\n<\/div>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Unit circle definition<br><\/strong>For this definition <em>\u03b8<\/em> is any angle.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"292\" height=\"274\" src=\"https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-2.png\" alt=\"Unit circle centered at the origin with x- and y-axes shown; a point labeled (x, y) on the circle in the first quadrant, a radius of length 1 from the origin to the point, angle \u03b8 measured from the positive x-axis, and dashed projections showing x on the horizontal axis and y on the vertical axis.\" class=\"wp-image-5361\"\/><\/figure>\n<\/div>\n\n\n$$\n\\sin \\theta = \\frac{y}{1} = y\n\\qquad\n\\csc \\theta = \\frac{1}{y}\n$$\n\n$$\n\\cos \\theta = \\frac{x}{1} = x\n\\qquad\n\\sec \\theta = \\frac{1}{x}\n$$\n\n$$\n\\tan \\theta = \\frac{y}{x}\n\\qquad\n    \n\\cot \\theta = \\frac{x}{y}\n$$\n<\/div>\n<\/div>\n\n\n\n<div style=\"height:20px\" aria-hidden=\"true\" class=\"wp-block-spacer\"><\/div>\n\n\n\n<h2 class=\"wp-block-heading has-text-align-center has-medium-font-size\">Facts and Properties<\/h2>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Domain<\/strong><br>The domain is all the values of <em>\u03b8<\/em> that<br>can be plugged into the function.<\/p>\n\n\n\n$$\n\\sin \\theta,\\quad \\theta \\text{ can be any angle}\n$$\n\n$$\n\\cos \\theta,\\quad \\theta \\text{ can be any angle}\n$$\n\n$$\n\\tan \\theta,\\quad \\theta \\ne \\left(n + \\frac{1}{2}\\right)\\pi,\\; n = 0, \\pm 1, \\pm 2, \\ldots\n$$\n\n$$\n\\csc \\theta,\\quad \\theta \\ne n\\pi,\\; n = 0, \\pm 1, \\pm 2, \\ldots\n$$\n\n$$\n\\sec \\theta,\\quad \\theta \\ne \\left(n + \\frac{1}{2}\\right)\\pi,\\; n = 0, \\pm 1, \\pm 2, \\ldots\n$$\n\n$$\n\\cot \\theta,\\quad \\theta \\ne n\\pi,\\; n = 0, \\pm 1, \\pm 2, \\ldots\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Range<\/strong><br>The range is all possible values to get<br>out of the function.<\/p>\n\n\n\n$$\n-1 \\le \\sin \\theta \\le 1\n\\qquad\n\\csc \\theta \\ge 1 \\;\\text{and}\\; \\csc \\theta \\le -1\n$$\n\n$$\n-1 \\le \\cos \\theta \\le 1\n\\qquad\n\\sec \\theta \\ge 1 \\;\\text{and}\\; \\sec \\theta \\le -1\n$$\n\n$$\n-\\infty < \\tan \\theta < \\infty\n\\qquad\n-\\infty < \\cot \\theta < \\infty\n$$\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Period<\/strong><br>The period of a function is the number, <em>T<\/em>, such that <em>f<\/em>(<em>\u03b8<\/em> + <em>T<\/em>) = <em>f<\/em>(<em>\u03b8<\/em>). So, if <em>\u03c9<\/em> is a fixed number and <em>\u03b8<\/em> is any angle, we have the following periods.<\/p>\n\n\n\n$$\n\\sin(\\omega \\theta) \\;\\rightarrow\\; T = \\frac{2\\pi}{\\omega}\n$$\n\n$$\n\\cos(\\omega \\theta) \\;\\rightarrow\\; T = \\frac{2\\pi}{\\omega}\n$$\n\n$$\n\\tan(\\omega \\theta) \\;\\rightarrow\\; T = \\frac{\\pi}{\\omega}\n$$\n\n$$\n\\csc(\\omega \\theta) \\;\\rightarrow\\; T = \\frac{2\\pi}{\\omega}\n$$\n\n$$\n\\sec(\\omega \\theta) \\;\\rightarrow\\; T = \\frac{2\\pi}{\\omega}\n$$\n\n$$\n\\cot(\\omega \\theta) \\;\\rightarrow\\; T = \\frac{\\pi}{\\omega}\n$$\n<\/div>\n<\/div>\n\n\n\n<div style=\"height:20px\" aria-hidden=\"true\" class=\"wp-block-spacer\"><\/div>\n\n\n\n<h2 class=\"wp-block-heading has-text-align-center has-medium-font-size\">Formulas and Identities<\/h2>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Tangent and Cotangent Identities<\/strong><\/p>\n\n\n\n$$\n\\tan \\theta = \\frac{\\sin \\theta}{\\cos \\theta}\n\\qquad\n\\cot \\theta = \\frac{\\cos \\theta}{\\sin \\theta}\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Reciprocal Identities<\/strong><\/p>\n\n\n\n$$\n\\sec \\theta = \\frac{1}{\\cos \\theta}\n\\qquad\n\\cos \\theta = \\frac{1}{\\sec \\theta}\n$$\n\n$$\n\\cot \\theta = \\frac{1}{\\tan \\theta}\n\\qquad\n\\tan \\theta = \\frac{1}{\\cot \\theta}\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Pythagorean Identities<\/strong><\/p>\n\n\n\n$$\n\\sin^2 \\theta + \\cos^2 \\theta = 1\n$$\n\n$$\n\\tan^2 \\theta + 1 = \\sec^2 \\theta\n$$\n\n$$\n1 + \\cot^2 \\theta = \\csc^2 \\theta\n$$\n\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Even\/Odd Formulas<\/strong><\/p>\n\n\n\n$$\n\\sin(-\\theta) = -\\sin \\theta\n\\qquad\n\\csc(-\\theta) = -\\csc \\theta\n$$\n\n$$\n\\cos(-\\theta) = \\cos \\theta\n\\qquad\n\\sec(-\\theta) = \\sec \\theta\n$$\n\n$$\n\\tan(-\\theta) = -\\tan \\theta\n\\qquad\n\\cot(-\\theta) = -\\cot \\theta\n$$\n\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Periodic Formulas<\/strong><br>If <em>n<\/em> is an integer.<\/p>\n\n\n\n$$\n\\sin(\\theta + 2\\pi n) = \\sin \\theta\n\\qquad\n\\csc(\\theta + 2\\pi n) = \\csc \\theta\n$$\n\n$$\n\\cos(\\theta + 2\\pi n) = \\cos \\theta\n\\qquad\n\\sec(\\theta + 2\\pi n) = \\sec \\theta\n$$\n\n$$\n\\tan(\\theta + \\pi n) = \\tan \\theta\n\\qquad\n\\cot(\\theta + \\pi n) = \\cot \\theta\n$$\n\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Double Angle Formulas<\/strong><\/p>\n\n\n\n$$\n\\sin(2\\theta) = 2 \\sin \\theta \\cos \\theta\n$$\n\n$$\n\\cos(2\\theta) = \\cos^2 \\theta &#8211; \\sin^2 \\theta\n$$\n\n$$\n\\cos(2\\theta) = 2 \\cos^2 \\theta &#8211; 1\n$$\n\n$$\n\\cos(2\\theta) = 1 &#8211; 2 \\sin^2 \\theta\n$$\n\n$$\n\\tan(2\\theta) = \\frac{2 \\tan \\theta}{1 &#8211; \\tan^2 \\theta}\n$$\n\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Degrees to Radians Formulas<\/strong><br>If <em>x<\/em> is an angle in degrees and <em>t<\/em> is an<br>angle in radians then<\/p>\n\n\n\n$$\n\\frac{\\pi}{180} = \\frac{t}{x}\n\\;\\Rightarrow\\;\nt = \\frac{\\pi x}{180}\n\\;\\text{and}\\;\nx = \\frac{180t}{\\pi}\n$$\n\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Half Angle Formulas<\/strong><\/p>\n\n\n\n$$\n\\sin \\frac{\\theta}{2}\n= \\pm \\sqrt{\\frac{1 &#8211; \\cos \\theta}{2}}\n$$\n\n$$\n\\cos \\frac{\\theta}{2}\n= \\pm \\sqrt{\\frac{1 + \\cos \\theta}{2}}\n$$\n\n\n\n$$\n\\tan \\frac{\\theta}{2}\n= \\pm \\sqrt{\\frac{1 &#8211; \\cos \\theta}{1 + \\cos \\theta}}\n$$\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>(alternate form)<\/strong><\/p>\n\n\n\n$$\n\\sin^2 \\theta\n= \\frac{1}{2}\\bigl(1 &#8211; \\cos(2\\theta)\\bigr)\n$$\n\n$$\n\\cos^2 \\theta\n= \\frac{1}{2}\\bigl(1 + \\cos(2\\theta)\\bigr)\n$$\n\n$$\n\\tan^2 \\theta\n= \\frac{1 &#8211; \\cos(2\\theta)}{1 + \\cos(2\\theta)}\n$$\n<\/div>\n<\/div>\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Sum and Difference Formulas<\/strong><\/p>\n\n\n\n$$\n\\sin(\\alpha \\pm \\beta)\n= \\sin \\alpha \\cos \\beta \\pm \\cos \\alpha \\sin \\beta\n$$\n\n$$\n\\cos(\\alpha \\pm \\beta)\n= \\cos \\alpha \\cos \\beta \\mp \\sin \\alpha \\sin \\beta\n$$\n\n$$\n\\tan(\\alpha \\pm \\beta)\n= \\frac{\\tan \\alpha \\pm \\tan \\beta}{1 \\mp \\tan \\alpha \\tan \\beta}\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Product to Sum Formulas<\/strong><\/p>\n\n\n\n$$\n\\sin \\alpha \\sin \\beta\n= \\frac{1}{2}\\bigl[\\cos(\\alpha &#8211; \\beta) &#8211; \\cos(\\alpha + \\beta)\\bigr]\n$$\n\n$$\n\\cos \\alpha \\cos \\beta\n= \\frac{1}{2}\\bigl[\\cos(\\alpha &#8211; \\beta) + \\cos(\\alpha + \\beta)\\bigr]\n$$\n\n$$\n\\sin \\alpha \\cos \\beta\n= \\frac{1}{2}\\bigl[\\sin(\\alpha + \\beta) + \\sin(\\alpha &#8211; \\beta)\\bigr]\n$$\n\n$$\n\\cos \\alpha \\sin \\beta\n= \\frac{1}{2}\\bigl[\\sin(\\alpha + \\beta) &#8211; \\sin(\\alpha &#8211; \\beta)\\bigr]\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Sum to Product Formulas<\/strong><\/p>\n\n\n\n$$\n\\sin \\alpha + \\sin \\beta\n= 2 \\sin\\!\\left(\\frac{\\alpha + \\beta}{2}\\right)\n  \\cos\\!\\left(\\frac{\\alpha &#8211; \\beta}{2}\\right)\n$$\n\n$$\n\\sin \\alpha &#8211; \\sin \\beta\n= 2 \\cos\\!\\left(\\frac{\\alpha + \\beta}{2}\\right)\n  \\sin\\!\\left(\\frac{\\alpha &#8211; \\beta}{2}\\right)\n$$\n\n$$\n\\cos \\alpha + \\cos \\beta\n= 2 \\cos\\!\\left(\\frac{\\alpha + \\beta}{2}\\right)\n  \\cos\\!\\left(\\frac{\\alpha &#8211; \\beta}{2}\\right)\n$$\n\n$$\n\\cos \\alpha &#8211; \\cos \\beta\n= -2 \\sin\\!\\left(\\frac{\\alpha + \\beta}{2}\\right)\n   \\sin\\!\\left(\\frac{\\alpha &#8211; \\beta}{2}\\right)\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Cofunction Formulas<\/strong><\/p>\n\n\n\n$$\n\\sin\\!\\left(\\frac{\\pi}{2} &#8211; \\theta\\right) = \\cos \\theta\n\\qquad\n\\cos\\!\\left(\\frac{\\pi}{2} &#8211; \\theta\\right) = \\sin \\theta\n$$\n\n$$\n\\csc\\!\\left(\\frac{\\pi}{2} &#8211; \\theta\\right) = \\sec \\theta\n\\qquad\n\\sec\\!\\left(\\frac{\\pi}{2} &#8211; \\theta\\right) = \\csc \\theta\n$$\n\n$$\n\\tan\\!\\left(\\frac{\\pi}{2} &#8211; \\theta\\right) = \\cot \\theta\n\\qquad\n\\cot\\!\\left(\\frac{\\pi}{2} &#8211; \\theta\\right) = \\tan \\theta\n$$\n\n<\/div>\n<\/div>\n\n\n\n<div style=\"height:20px\" aria-hidden=\"true\" class=\"wp-block-spacer\"><\/div>\n\n\n\n<h2 class=\"wp-block-heading has-text-align-center has-medium-font-size\">Unit Circle<\/h2>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"999\" height=\"1024\" src=\"https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-3-999x1024.png\" alt=\"Unit circle centered at the origin with x- and y-axes labeled; angles marked in both degrees and radians around the circle, and key points labeled with their coordinates, including (1,0), (0,1), (\u22121,0), (0,\u22121), and standard special-angle coordinates such as (\u221a3\u20442, 1\u20442), (\u221a2\u20442, \u221a2\u20442), (1\u20442, \u221a3\u20442), and their corresponding negatives in each quadrant.\" class=\"wp-image-5391\" style=\"width:540px;height:auto\" srcset=\"https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-3-999x1024.png 999w, https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-3-293x300.png 293w, https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-3-768x787.png 768w, https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-3.png 1444w\" sizes=\"auto, (max-width: 999px) 100vw, 999px\" \/><\/figure>\n<\/div>\n\n\n<p class=\"has-text-align-center wp-block-paragraph\">For any ordered pair on the unit circle ( <em>x<\/em>, <em>y<\/em> ) : cos <em>\u03b8<\/em> = <em>x<\/em> and sin <em>\u03b8<\/em> = <em>y<\/em><\/p>\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Example<\/strong><\/p>\n\n\n\n$$\n\\cos\\!\\left(\\frac{5\\pi}{3}\\right) = \\frac{1}{2}\n\\qquad\n\\sin\\!\\left(\\frac{5\\pi}{3}\\right) = -\\frac{\\sqrt{3}}{2}\n$$\n\n\n\n<div style=\"height:20px\" aria-hidden=\"true\" class=\"wp-block-spacer\"><\/div>\n\n\n\n<h2 class=\"wp-block-heading has-text-align-center has-medium-font-size\">Inverse Trig Functions<\/h2>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Definition<\/strong><br><em>y<\/em> = sin<sup>\u22121<\/sup> <em>x<\/em> is equivalent to <em>x<\/em> = sin <em>y<\/em><br><em>y<\/em> = cos<sup>\u22121<\/sup> <em>x<\/em> is equivalent to <em>x<\/em> = cos <em>y<\/em><br><em>y<\/em> = tan<sup>\u22121<\/sup> <em>x<\/em> is equivalent to <em>x<\/em> = tan <em>y<\/em><\/p>\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Domain and Range<\/strong><\/p>\n\n\n\n$$\n\\begin{array}{c c c}\n\\textbf{Function} &#038; \\textbf{Domain} &#038; \\textbf{Range} \\\\[6pt]\ny = \\sin^{-1} x &#038; -1 \\le x \\le 1 &#038; -\\dfrac{\\pi}{2} \\le y \\le \\dfrac{\\pi}{2} \\\\[6pt]\ny = \\cos^{-1} x &#038; -1 \\le x \\le 1 &#038; 0 \\le y \\le \\pi \\\\[6pt]\ny = \\tan^{-1} x &#038; -\\infty < x < \\infty &#038; -\\dfrac{\\pi}{2} < y < \\dfrac{\\pi}{2}\n\\end{array}\n$$\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Inverse Properties<\/strong><\/p>\n\n\n\n$$\n\\cos\\!\\bigl(\\cos^{-1}(x)\\bigr) = x\n\\qquad\n\\cos^{-1}\\!\\bigl(\\cos(\\theta)\\bigr) = \\theta\n$$\n\n$$\n\\sin\\!\\bigl(\\sin^{-1}(x)\\bigr) = x\n\\qquad\n\\sin^{-1}\\!\\bigl(\\sin(\\theta)\\bigr) = \\theta\n$$\n\n$$\n\\tan\\!\\bigl(\\tan^{-1}(x)\\bigr) = x\n\\qquad\n\\tan^{-1}\\!\\bigl(\\tan(\\theta)\\bigr) = \\theta\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Alternate Notation<\/strong><\/p>\n\n\n\n$$\n\\sin^{-1} x = \\arcsin x\n$$\n\n$$\n\\cos^{-1} x = \\arccos x\n$$\n\n$$\n\\tan^{-1} x = \\arctan x\n$$\n\n<\/div>\n<\/div>\n\n\n\n<div style=\"height:20px\" aria-hidden=\"true\" class=\"wp-block-spacer\"><\/div>\n\n\n\n<h2 class=\"wp-block-heading has-text-align-center has-medium-font-size\">Law of Sines, Cosines and Tangents<\/h2>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"758\" height=\"448\" src=\"https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-4.png\" alt=\"Scalene triangle with sides labeled a, b, and c; the base is side b, the left side is c, and the right side is a, with angles labeled \u03b1 at the left base, \u03b2 at the top vertex, and \u03b3 at the right base.\" class=\"wp-image-5398\" style=\"width:372px;height:auto\" srcset=\"https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-4.png 758w, https:\/\/www.eastcentral.edu\/learning-center\/wp-content\/uploads\/sites\/27\/2025\/12\/image-4-300x177.png 300w\" sizes=\"auto, (max-width: 758px) 100vw, 758px\" \/><\/figure>\n<\/div>\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Law of Sines<\/strong><\/p>\n\n\n\n$$\n\\frac{\\sin \\alpha}{a}\n= \\frac{\\sin \\beta}{b}\n= \\frac{\\sin \\gamma}{c}\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Law of Cosines<\/strong><\/p>\n\n\n\n$$\na^2 = b^2 + c^2 &#8211; 2bc \\cos \\alpha\n$$\n\n$$\nb^2 = a^2 + c^2 &#8211; 2ac \\cos \\beta\n$$\n\n$$\nc^2 = a^2 + b^2 &#8211; 2ab \\cos \\gamma\n$$\n\n\n\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Mollweide\u2019s Formula<\/strong><\/p>\n\n\n\n$$\n\\frac{a + b}{c}\n= \\frac{\\cos\\!\\left(\\tfrac{1}{2}(\\alpha &#8211; \\beta)\\right)}\n       {\\sin\\!\\left(\\tfrac{1}{2}\\gamma\\right)}\n$$\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p class=\"has-text-align-center wp-block-paragraph\"><strong>Law of Tangents<\/strong><\/p>\n\n\n\n$$\n\\frac{a &#8211; b}{a + b}\n= \\frac{\\tan\\!\\left(\\tfrac{1}{2}(\\alpha &#8211; \\beta)\\right)}\n       {\\tan\\!\\left(\\tfrac{1}{2}(\\alpha + \\beta)\\right)}\n$$\n\n$$\n\\frac{b &#8211; c}{b + c}\n= \\frac{\\tan\\!\\left(\\tfrac{1}{2}(\\beta &#8211; \\gamma)\\right)}\n       {\\tan\\!\\left(\\tfrac{1}{2}(\\beta + \\gamma)\\right)}\n$$\n\n$$\n\\frac{a &#8211; c}{a + c}\n= \\frac{\\tan\\!\\left(\\tfrac{1}{2}(\\alpha &#8211; \\gamma)\\right)}\n       {\\tan\\!\\left(\\tfrac{1}{2}(\\alpha + \\gamma)\\right)}\n$$\n<\/div>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Definition of the Trig Functions Right triangle definitionFor this definition we assume that $$ 0 < \\theta < \\frac{\\pi}{2} \\quad \\text{or} \\quad 0^\\circ < \\theta < 90^\\circ $$ $$ \\sin \\theta = \\frac{\\text{opposite}}{\\text{hypotenuse}} \\qquad $$ $$ \\cos \\theta = \\frac{\\text{adjacent}}{\\text{hypotenuse}} \\qquad $$ $$ \\tan \\theta = \\frac{\\text{opposite}}{\\text{adjacent}} \\qquad $$ $$ \\csc \\theta = \\frac{\\text{hypotenuse}}{\\text{opposite}} $$ [&hellip;]\n<\/p>\n","protected":false},"author":98,"featured_media":0,"parent":3836,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"template\/template-full-page.php","meta":{"_eb_attr":"","footnotes":""},"yst_prominent_words":[],"class_list":["post-5347","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/pages\/5347","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/users\/98"}],"replies":[{"embeddable":true,"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/comments?post=5347"}],"version-history":[{"count":48,"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/pages\/5347\/revisions"}],"predecessor-version":[{"id":5411,"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/pages\/5347\/revisions\/5411"}],"up":[{"embeddable":true,"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/pages\/3836"}],"wp:attachment":[{"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/media?parent=5347"}],"wp:term":[{"taxonomy":"yst_prominent_words","embeddable":true,"href":"https:\/\/www.eastcentral.edu\/learning-center\/wp-json\/wp\/v2\/yst_prominent_words?post=5347"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}